A) 882
B) 1323
C) 1764
D) 3528
Correct Answer: D
Solution :
\[{{1}^{3}}+{{2}^{3}}+{{3}^{3}}+{{4}^{4}}+{{5}^{3}}+{{6}^{3}}=441\] \[{{2}^{3}}+{{4}^{4}}+{{6}^{3}}+{{8}^{3}}+{{10}^{3}}+{{12}^{3}}\] \[=8({{1}^{3}}+{{2}^{3}}+{{3}^{3}}+{{4}^{4}}+{{5}^{3}}+{{6}^{3}})\] \[=8\times 441=3528\]You need to login to perform this action.
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