A) 3
B) 5
C) 7
D) 11
Correct Answer: C
Solution :
\[x+y+z=3\times 45=135\] \[x=\frac{y+z}{2}+9\] ?(i) \[\Rightarrow \] \[2x-y-z=18\] ...(ii) and \[\frac{y+z}{2}=y+2\] \[\Rightarrow \] \[y+z=2y+4\] \[\Rightarrow \] \[z-y=7\] ?(iii) By Eqs. (i) + (ii), \[3x=135+18=153\] \[\Rightarrow \] \[x=51\] By Eqs. (i) and (iii), \[x+y+z+z-y\] \[=135+4=139\] \[\Rightarrow \] \[x+2z=139\] \[\Rightarrow \] \[51+2z=139\] \[\Rightarrow \] \[2z=139-51=88\] \[\therefore \] \[z=44\] \[\therefore \] \[x-z=51-44=7\]You need to login to perform this action.
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