A) 200 m
B) 300 m
C) 350 m
D) 400 m
Correct Answer: D
Solution :
Let the length of the train travelling at 48 km/h be x m Let the length of the platform be y m. Relative speed of train \[=(48+42)\,\text{km/h}\] \[=\frac{90\times 5}{18}\text{m/s}\] \[=25\,\text{m/s}\] and 48 km\[=\frac{48\times 5}{18}=\frac{40}{3}\text{m/s}\] According to the question, \[\frac{x+\frac{x}{2}}{25}=12\] \[\Rightarrow \] \[\frac{3x}{2\times 25}=12\] \[\Rightarrow \] \[3x=2\times 12\times 25=600\] \[\Rightarrow \] \[x=200\,m\] Case II \[\frac{200+y}{40/3}=45\] \[\Rightarrow \] \[600+3y=40\times 45\] \[\Rightarrow \] \[3y=1800-600=1200\] \[\Rightarrow \] \[y=\frac{1200}{3}=400\,\,m\]You need to login to perform this action.
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