A) \[\frac{3}{4}{{S}_{2}}\]
B) \[\frac{1}{2}{{S}_{2}}\]
C) \[\frac{2}{3}{{S}_{2}}\]
D) \[{{S}_{2}}\]
Correct Answer: B
Solution :
\[{{S}_{1}}=\text{Surface area of sphere}=4\pi {{r}^{2}}\] \[{{S}_{2}}=\] Curved surface of the circumscribed Cylinder \[=2\pi RH\] \[=2\pi (2r)(2r)\] \[=8\pi {{r}^{2}}\] \[\therefore \] \[\frac{{{S}_{1}}}{{{S}_{2}}}=\frac{4{{\pi }^{2}}}{8\pi {{r}^{2}}}=\frac{1}{2}\] \[\Rightarrow \] \[{{S}_{1}}=\frac{1}{2}{{S}_{2}}\]You need to login to perform this action.
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