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SSC Sample Paper SSC CGL - Sample Paper-17

  • question_answer
    If \[{{S}_{1}}\] and \[{{S}_{2}}\] be the surface area of a sphere and the curved surface area of the circumscribed cylinder respectively, then \[{{S}_{1}}\] is equal to

    A) \[\frac{3}{4}{{S}_{2}}\]                      

    B) \[\frac{1}{2}{{S}_{2}}\]

    C) \[\frac{2}{3}{{S}_{2}}\]                                  

    D) \[{{S}_{2}}\]

    Correct Answer: B

    Solution :

    \[{{S}_{1}}=\text{Surface area of sphere}=4\pi {{r}^{2}}\] \[{{S}_{2}}=\] Curved surface of the circumscribed Cylinder             \[=2\pi RH\]             \[=2\pi (2r)(2r)\]             \[=8\pi {{r}^{2}}\] \[\therefore \]      \[\frac{{{S}_{1}}}{{{S}_{2}}}=\frac{4{{\pi }^{2}}}{8\pi {{r}^{2}}}=\frac{1}{2}\] \[\Rightarrow \]   \[{{S}_{1}}=\frac{1}{2}{{S}_{2}}\]


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