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SSC Sample Paper SSC CGL - Sample Paper-16

  • question_answer
    If \[{{(102)}^{2}}=10404,\]then the value of \[\sqrt{104.04}+\sqrt{1.0404}+\sqrt{0.010404}\] is equal to

    A) 0.306               

    B) 0.0306

    C) 11.122             

    D) 11.322

    Correct Answer: D

    Solution :

    \[\because \] \[{{(102)}^{2}}=10404\] \[\Rightarrow \]   \[\sqrt{10404}=102\]             \[\sqrt{104.04}+\sqrt{1.0404}+\sqrt{0.010404}\]             \[=10.2+1.02+0.102\]             \[=11.322\]


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