2. Sample Papers
  3. SSC

SSC Sample Paper SSC CGL - Sample Paper-16

  • question_answer
    If \[{{x}^{2}}=y+z,\] \[{{y}^{2}}=z+x,\] \[{{z}^{2}}=x+y,\] then the value of \[\frac{1}{x+y}+\frac{1}{y+1}+\frac{1}{z+1}\] is

    A) \[-1\]                            

    B) 1

    C) 2                                 

    D) 4

    Correct Answer: B

    Solution :

    \[{{x}^{2}}=y+z\] \[\Rightarrow \]   \[{{x}^{2}}+x=x+y+z\] \[\Rightarrow \]   \[x(x+1)=x+y+z\]                     ? (i) Similarly,             \[y(y+1)=x+y+z\]                     ? (ii) and       \[z(z+1)=x+y+z\]                      ?(iii) \[\therefore \]      \[\frac{1}{x+1}+\frac{1}{y+1}+\frac{1}{z+1}\] \[=\frac{x}{x+y+z}+\frac{y}{x+y+z}+\frac{z}{x+y+z}\] \[=\frac{x+y+z}{x+y+z}=1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner