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SSC Sample Paper SSC CGL - Sample Paper-16

  • question_answer
    If  \[{{(10.15)}^{2}}=103.0225,\] then   the   value of \[\sqrt{1.030225}+\sqrt{10302.25}\] is

    A) 1025.15            

    B) 103.515

    C) 102.515

    D) 102.0515

    Correct Answer: C

    Solution :

    \[{{(10.15)}^{2}}=103.0225\] \[\Rightarrow \]   \[{{(1.125)}^{2}}=1.030225\] and       \[{{(101.5)}^{2}}=10302.25\] \[\therefore \]\[\sqrt{1.030225}+\sqrt{10302.25}\]             \[=\sqrt{{{(0.015)}^{2}}}+\sqrt{{{(101.5)}^{2}}}\]             \[=1.015+101.5\]             = 102.515        


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