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SSC Sample Paper SSC CGL - Sample Paper-12

  • question_answer
    The sides of a triangle are in the ratio 2: 3: 4. The perimeter of the triangle is 18 cm. The area (in \[c{{m}^{2}}\]) of the triangle is

    A) 9                                 

    B) 36

    C) \[\sqrt{42}\]                              

    D) \[3\sqrt{15}\]

    Correct Answer: D

    Solution :

    Ratio = 2 : 3 : 4 = 4 : 6 : 8 Perimeter = 18 cm \[\therefore \] Semi-perimeter (s) \[=\frac{4+6+8}{2}=9\] \[\therefore \] Area of triangle \[=\sqrt{s(s-a)(s-b)(s-c)}\]                         \[=\sqrt{9(9-4)(9-6)(9-8)}\]                         \[=\sqrt{9\times 5\times 3\times 1}=3\sqrt{5}\,sq\,cm\]


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