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SSC Sample Paper SSC CGL - Sample Paper-11

  • question_answer
    Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there are three persons ahead of C and 21 behind A, then what could be the minimum number of persons in the queue?

    A) 27                                

    B) 28      

    C) 40                                

    D) 41

    Correct Answer: B

    Solution :

    As per the given conditions, there are two possible arrangements as shown below \[\begin{align}   & \overset{21}{\longleftrightarrow}A\overset{5}{\longleftrightarrow}B\overset{8}{\longleftrightarrow}C\overset{3}{\longleftrightarrow}\overset{21}{\longleftrightarrow} \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,I \\ \end{align}\] \[\begin{align}   & \overset{3}{\longleftrightarrow}C\overset{2}{\longleftrightarrow}A\overset{5}{\longleftrightarrow}B\overset{8}{\longleftrightarrow} \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,II \\ \end{align}\] Clearly, for the minimum number of persons, we shall consider arrangement II. In II, number of persons in the queue \[=(3+1+2+1+21)=28.\]


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