A) \[64\sqrt{3}\]
B) 81
C) \[192\sqrt{3}\]
D) \[3\sqrt{2}\]
Correct Answer: C
Solution :
Diagonal of cube \[=\sqrt{3{{a}^{2}}}\] \[\therefore \] According to question, \[12=\sqrt{3{{a}^{2}}}\] or, \[3{{a}^{2}}12\times 12\] \[\Rightarrow \] \[a=4\sqrt{3}\,cm\] \[\therefore \] Volume \[={{a}^{3}}=(4{{\sqrt{3}}^{3}})\,cu\,cm\] \[192\sqrt{3}\,cu\,\,cm\]
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