A) 5 days
B) \[7\frac{5}{6}\]days
C) 10 days
D) \[15\frac{2}{3}\] days
Correct Answer: C
Solution :
According to question, A and B can do a work in 12 days \[\therefore \] (A + B)?s one days's work \[=\frac{1}{12}\] Similarly, (B + C)?s one day's work \[=\frac{1}{15}\] And (C + A)?s one day's work \[=\frac{1}{20}\] \[\therefore \] (A + B + C)?s one day's work \[=\frac{1}{12}+\frac{1}{15}+\frac{1}{20}=\frac{10+8+6}{120}=\frac{1}{5}\] (A + B + C)?s one day's work \[=\frac{1}{10}\] \[\therefore \] A, B and C together can finish the whole work in 10 days.
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