A) 42 cm
B) 52 cm
C) 54 cm
D) 56 cm
Correct Answer: D
Solution :
Let the base and altitude be 3x and 4x respectively. \[\therefore \] According to question, \[\frac{1}{2}\text{base}\times \text{altitude}\,\,\text{=}\,\,\text{1176}\,\,\text{c}{{\text{m}}^{2}}\] or, \[\frac{1}{2}\times 3x\times 4x\,\,\text{=}\,\,\text{1176}\] \[12{{x}^{2}}=1176\times 2\] \[{{x}^{2}}=\frac{1176\times 2}{12}\] or, \[{{x}^{2}}=196\] \[x=\sqrt{196}=14\,cm.\] \[\therefore \] Altitude of a triangle \[=4x\] \[=4\times 14\,cm=56\,cm\]
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