A) 16, 121
B) 22, 88
C) 44, 44
D) None of these.
Correct Answer: B
Solution :
[b] Let one number = a \[\therefore \,\] Second number = 4 a \[\Rightarrow \] \[4a\times a=1936\] \[\Rightarrow \] \[{{a}^{2}}=\frac{1936}{4}=484\] \[\Rightarrow \] \[{{a}^{2}}=484\] \[\Rightarrow \] \[a=2\times 11=22\] and \[4a=4\times 22=88\] \[\therefore \,\] Numbers are 22 and 88.You need to login to perform this action.
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