A) Rs. 122
B) Rs. 130
C) Rs. 150
D) Rs. 145
Correct Answer: A
Solution :
[a] \[C.I.=2000\left[ {{\left( 1+\frac{8}{100\times 4} \right)}^{4\times \frac{9}{12}}}-1 \right]\] P = 2000, R = 8% p.a. t = 9 months \[=\frac{9}{12}\,year\] \[C.I.=2000\left[ {{\left( 1+\frac{8}{100\times 4} \right)}^{4\times \frac{9}{12}}}-1 \right](n=4)\] \[=2000\left[ {{\left( \frac{102}{100} \right)}^{3}}-1 \right]=Rs.\,122.\] \[\therefore \] The compound interest is Rs. 122
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