Direction: Study the given table carefully to answer the following questions: | |||||||
Station | Arrival time | Departure time | Halt time (in minutes) | Distance travelled from origin (in km) | Fare (Rs.) | Number of passengers boarding the train at each station | Number of passengers deboarding the train at each station |
Delhi | Starting | 5.45 pin | - | 0 km | - | 500 | - |
Mathura | 7.00 pm | 7.05 pm | 5 | 100 | 60 | 200 | 80 |
Agra | 8.30 pm | 8.35 pm | 5 | 210 | 130 | 350 | 50 |
Jhansi | 11.45 pm | 12.00 night | 15 | 400 | 250 | 250 | 100 |
Bhopal | 3.58 am | 4.05 am | 7 | 720 | 375 | 180 | 200 |
Itarsi | 7.35 am | 7.48 am | 13 | 1000 | 425 | 150 | 150 |
Nagpur | 12.00 noon | Terminates | 1350 | 510 |
A) 8.6%
B) 2.4%
C) 7.8%
D) 5.6%
E) 4.1%
Correct Answer: E
Solution :
Total travel time = 12.00 noon - 5.45 pm (one day before) = 18hr 15min \[=18+\frac{15}{60}\]hours \[=\frac{73}{4}\]hours Total halt time = 5 + 5 + 15 + 7 + 13 = 45 minutes Total halt time is\[\frac{45}{60}=\frac{3}{5}\] hours \[\therefore \]Reqd% \[=\frac{3}{4}\times \frac{4}{73}\times 100\] = 4.10% of the total travel time.You need to login to perform this action.
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