A) \[93\,\,{{m}^{2}}\]
B) \[99\,\,{{m}^{2}}\]
C) \[96\,\,{{m}^{2}}\]
D) \[95\,\,{{m}^{2}}\]
E) None of these
Correct Answer: E
Solution :
Perimeter of the field\[=\frac{200}{4}=50\,\,m\] Ratio of length to breadth\[=150:100=3:2\] Also we have, length + breadth\[=\frac{50}{2}=25\] \[\therefore \]Length\[=\frac{25}{5}\times 3=15\] \[\therefore \]Breadth = 10 \[\therefore \]Area\[=15\times 10=150\,\,sq\,\,m\]You need to login to perform this action.
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