question_answer

Direction: In the question, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. Give answer

(i) if\[x>y\]

(ii) if\[x\le y\]

(iii) if \[x<y\]

(iv) if\[x\ge y\]

(v) if\[x=y\]or relationship between\[x\]and\[y\]can't be established

I. \[{{x}^{2}}+16x+64=0\]

II. \[{{y}^{2}}+11y=0\]

A)  if x>y            

B)  if x<y

C)  if x<y

D)       if x>y

E)  if x=y or relationship between x and y can't be established.

Correct Answer: E

Solution :

Step II. \[+\frac{8}{1}\]             \[+\frac{8}{1}\] Step III. \[x=-8\] II. \[{{y}^{2}}+11y=0\] Step I. \[y(y+11)=0\] Step II. \[y=0,-11\] Hence no relationship can be established between x and y.