A) \[\operatorname{p}\times 2q\times 3r = 6pq\] [monomial]
B) \[\operatorname{p}\times 2q\times 3r = 8pq\] [monomial]
C) \[\operatorname{p}\times 3q\times 2r = 8pq\] [monomial]
D) \[\operatorname{p}\times 8q\times 2r = 6pq\] [monomial]
Correct Answer: A
Solution :
\[\operatorname{p}\times 2q\times 3r = 6pq\] [monomial]You need to login to perform this action.
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