question_answer

One of the angle of a parallelogram is \[55{}^\circ .\] The remaining angles are respectively

A)  \[105{}^\circ ,125{}^\circ ,55{}^\circ \]

B)  \[125{}^\circ ,55{}^\circ ,125{}^\circ \]

C)  \[125{}^\circ ,125{}^\circ ,55{}^\circ \]

D)  \[25{}^\circ ,135{}^\circ ,135{}^\circ \]

Correct Answer: C

Solution :

\[\angle A+\angle B=180{}^\circ \]             \[\because \]       \[\,AD||BC\] \[\therefore \]\[\angle B=180{}^\circ -55{}^\circ =125{}^\circ \]             Also,     \[\angle B=\angle D=125{}^\circ \]                         \[\angle A=\angle C=55{}^\circ \]