A) 9.8 m
B) 19.6m
C) 39.2 m
D) Data inadequate
Correct Answer: B
Solution :
Given, t = 2 s Initial velocity of stone, u = 0 The height of the bridge can be obtained by the equations of motion \[s=ut+\frac{1}{2\,}a{{t}^{2}}\] For free fall the equation is h \[=ut+\frac{1}{2}g{{t}^{2}}\] \[\therefore \,\]Height of bridge, h\[=0\times t+\frac{1}{2}\times 9.8\times {{2}^{2}}\] \[(g=9.8m{{s}^{-2}})\] = 19.6 m
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