A) 1154
B) 1158
C) 1160
D) 1164
Correct Answer: A
Solution :
\[a+\frac{1}{a}=6\Rightarrow {{\left( a+\frac{1}{a} \right)}^{2}}={{(6)}^{2}}\] \[\Rightarrow \] \[{{a}^{2}}+\frac{1}{{{a}^{2}}}+2=36\] \[\Rightarrow \] \[{{a}^{2}}+\frac{1}{{{a}^{2}}}=36-2=34\] \[\Rightarrow \] \[\left( {{a}^{2}}+\frac{1}{{{a}^{2}}} \right)={{(34)}^{2}}\] \[\Rightarrow \] \[{{a}^{4}}+\frac{1}{{{a}^{4}}}+2=1156\] \[\therefore \] \[{{a}^{4}}+\frac{1}{{{a}^{4}}}=1156-2=1154\]You need to login to perform this action.
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