A) 36 km/h
B) 54 km/h
C) 50 km/h
D) 45 km/h
Correct Answer: B
Solution :
Sped of first train \[=\frac{150}{15}=10\,\,m/s\] Second case,\[\frac{150+150}{x+10}=12,\] where x = speed of other train \[\Rightarrow \,\] \[300=12x+120\] \[\Rightarrow \,\] \[x=\frac{180}{12}=15\,\,m/s\] \[\therefore \] Required speed \[=15\times \frac{18}{5}=54\,\,km/h\]You need to login to perform this action.
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