A) 4
B) 3
C) 5
D) 6
Correct Answer: B
Solution :
\[\begin{matrix} \text{R} & \text{A} & \text{T} & \text{L} & \text{A} & \text{M} \\ \end{matrix}\] \[18+1+20+12+1+13=65\] \[6+5=11=1+1=2\] \[\therefore \]\[\begin{matrix} \text{P} & \text{A} & \text{D} & \text{M} & \text{I} & \text{N} & \text{I} \\ \end{matrix}\] \[16+1+4+13+9+14+9=66\] \[6+6=12=1+2=3\]You need to login to perform this action.
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