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Railways Sample Paper RRBs Assistant Loco Pilot and Technician CBT STAGE-I Sample Paper-27

  • question_answer
    \[\frac{1}{(1+{{\tan }^{2}}\theta )}+\frac{1}{(1+{{\cot }^{2}}+\theta )}\]is equal to

    A)  \[\frac{1}{4}\] 

    B)         \[\frac{1}{2}\]    

    C)  1                    

    D)  2

    Correct Answer: C

    Solution :

    Given expression \[=\frac{1}{(1+{{\tan }^{2}}\theta )}+\frac{1}{{{(1+{{\cot }^{2}}\theta )}^{2}}}\] \[\frac{1}{{{\sec }^{2}}\theta }+\frac{1}{\cos e{{c}^{2}}\theta }=({{\cos }^{2}}\theta +{{\sin }^{2}}\theta )=1\]


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