A) 8
B) 14
C) 50
D) 51
Correct Answer: A
Solution :
\[({{x}^{n}}-1)\]is divisible by \[(x+1)\],when n is even. \[[{{(49)}^{15}}-1]=\{{{({{7}^{2}})}^{15}}-1\}=\{{{(7)}^{30}}-1\},\] which is divisible by\[(7+1),\]i.e. 8.You need to login to perform this action.
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