| 1 | 4 | ? |
| 4 | 2 | 5 |
| 2 | 2 | 3 |
| 49 | 64 | 169 |
A) 3
B) 1
C) 5
D) 6
Correct Answer: C
Solution :
In the first column, \[{{\left( 1+4+2 \right)}^{2}}=49\] In the second column, \[{{\left( 4+2+2 \right)}^{2}}=64\] Let the missing number be x. Then, in the third column we have \[{{(x+5+3)}^{2}}=169={{(13)}^{2}}\] \[\Rightarrow \] \[x+5+3=13\Rightarrow x=5\]
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