A) \[(2x-7)(x+7)(4x+3)\]
B) \[\left( x-2 \right)\left( x+7 \right)\left( 4x+3 \right)\]
C) \[\left( x-2 \right)\left( x+7 \right)\left( x+7 \right)\]
D) None of the above
Correct Answer: B
Solution :
\[\because \] \[4{{x}^{3}}+23{{x}^{2}}-41x-42\] is divisible by \[(x-2).\] \[\because \] \[4{{x}^{2}}+23{{x}^{2}}-41x-42\] \[=(x-2)(4{{x}^{2}}+31x+21)\] \[=(x-2)(4{{x}^{2}}+28x+3x+21)\] \[=(x-2)(x+7)(4x+3)\]
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