A) 1
B) \[-\,1\]
C) 0
D) \[\frac{1}{2}\]
Correct Answer: B
Solution :
[b] Given that, \[x+\frac{1}{y}=1\] \[\Rightarrow \,\,\,xy+1=y\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...(i)\] ?. (i) \[and\,\,\,y+\frac{1}{z}=1\] \[\Rightarrow \,\,\,1-\,\frac{1}{z}=y\] \[\Rightarrow \,\,\,\frac{z-\,1}{z}=y\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...(ii)\] ?. (ii) From eq. (ii), \[y=\frac{z-\,1}{z}\] Comparing eqn. (i) with (ii). \[xy+1=\frac{z-\,1}{z}\] \[\Rightarrow \,\,\,xyz+z=z-\,1\] \[\Rightarrow \,\,\,xyz=-\,1\]
You need to login to perform this action.
You will be redirected in
3 sec
