Railways Sample Paper RRB (Group D) Sample Test Paper-7

  • question_answer
    The average of odd numbers upto 100 is

    A)  50.5    

    B)  50

    C)  49.5    

    D)  49

    Correct Answer: B

    Solution :

    [b] Average of the first n natural odd numbers = n Number of odd numbers upto 100 = 50 = required average. No. of odd no upto 100 = 50 Sum of 50 odd no =\[{{50}^{2}}\] Average =\[\frac{50\times 50}{50}=50.\]


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