A) \[-\,2\]
B) 2
C) \[-\,1\]
D) 1
Correct Answer: C
Solution :
[c] \[{{\left( \frac{3}{5} \right)}^{3}}\,\,{{\left( \frac{3}{5} \right)}^{-\,6}}={{\left( \frac{3}{5} \right)}^{2x-\,1}}\] \[\Rightarrow {{\left( \frac{3}{5} \right)}^{3}}\,\,{{\left( \frac{3}{5} \right)}^{-\,3}}\,\,{{\left( \frac{3}{5} \right)}^{-\,3}}={{\left( \frac{3}{5} \right)}^{2x-\,1}}\] \[\Rightarrow {{\left( \frac{3}{5} \right)}^{0}}\,\,{{\left( \frac{3}{5} \right)}^{-\,3}}={{\left( \frac{3}{5} \right)}^{2x-\,1}}\] \[\Rightarrow \,\,\,2x-\,1=-\,3\] \[\Rightarrow \,\,\,2x=-\,3+1=-\,2\] \[\Rightarrow \,\,\,x=-\,1\]
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