| The sum of the series |
| \[(1+0.6+0.06+0.006+0.0006+...)\] is |
A) \[1\frac{2}{3}\]
B) \[1\frac{1}{3}\]
C) \[2\frac{1}{3}\]
D) \[2\frac{2}{3}\]
Correct Answer: A
Solution :
[a] \[1+0.6+0.06+0.006+0.0006+...=1.666...\] \[=1.\overline{6}=1\frac{6}{9}=1\frac{2}{3}\]
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