A) 2
B) 3
C) 4
D) 5
Correct Answer: B
Solution :
[b] If \[a+b+c=0\] Then \[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}=3\]abc Dividing both sides by abc \[\frac{{{a}^{3}}}{abc}+\frac{{{b}^{3}}}{abc}+\frac{{{3}^{3}}}{abc}=\frac{3abc}{abc}\] \[\frac{{{a}^{2}}}{bc}+\frac{{{b}^{2}}}{ac}+\frac{{{c}^{2}}}{ab}=3\]You need to login to perform this action.
You will be redirected in
3 sec