A) 8
B) 12
C) 20
D) 32
Correct Answer: C
Solution :
[c] According to question \[26<\sqrt{709}<27\] Now, \[{{(27)}^{2}}=729\] \[\therefore \,\,\,729-\,709=20\] \[\therefore \] 20 must be added to 709 to make it a perfect square.You need to login to perform this action.
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