A) 10000
B) 12000
C) 20000
D) 24000
Correct Answer: A
Solution :
[a] Let sum Rs. =x C.I. when compounded half yearly \[=\left[ x\,\,{{\left( 1+\frac{20}{200} \right)}^{4}}-\,x \right]=\frac{4641x}{10000}\] C.I. when compound annually \[=\left[ x\,\,{{\left( 1+\frac{20}{200} \right)}^{2}}-\,x \right]=\frac{11x}{25}\] Now, \[\frac{4641x}{10000}-\,\frac{11x}{25}=241\] \[\therefore \,\,\,x=10000\] \[\therefore \,\,sum=Rs.\,\,10000\]You need to login to perform this action.
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