A) \[{{(2)}^{\frac{1}{2}}}\]
B) 1
C) \[{{(6)}^{\frac{1}{6}}}\]
D) \[{{(3)}^{\frac{1}{3}}}\]
Correct Answer: D
Solution :
[d] LCM of 3, 2 and 6 =6 \[\therefore \,\,\,{{(3)}^{\frac{1}{3}}}={{({{3}^{2}})}^{\frac{1}{6}}}={{(9)}^{\frac{1}{6}}}\] \[{{2}^{\frac{1}{2}}}={{({{2}^{3}})}^{\frac{1}{6}}}={{(8)}^{\frac{1}{6}}}\] \[{{(1)}^{\frac{1}{6}}}=1\,\,;\,\,{{(6)}^{\frac{1}{6}}}={{(6)}^{\frac{1}{6}}}\]
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