A) 1 year
B) \[1\frac{1}{2}\] years
C) 2 years
D) 3 years
Correct Answer: C
Solution :
[c] Let total age of family be S years 3 years ago, total age\[=s-\,3\times 5=S-\,15\] \[\frac{S-\,15}{5}=17\] \[S=17\times 5+15=100\] Let present age of baby be x years \[\frac{S+x}{6}=17\] \[100+x=17\times 6\] \[x=102-\,100=2\,\,Year\]
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