• # question_answer A and B are two taps which can fill a tank individually in 10 minutes and 20 minutes respectively. However, there is a leakage at the bottom which can empty a filled tank in 40 minutes. If the tank is empty initially, how much time will both the taps take to fill the tank (leakage is still there)? A)  8 minutes                      B)  7 minutes C)  10 minutes         D)       15 minutes

Correct Answer: A

Solution :

Part of the tank filled in 1 minute           $=\frac{1}{10}+\frac{1}{20}-\frac{1}{40}$            $=\frac{4+2-1}{40}=\frac{5}{40}=\frac{1}{8}$ $\therefore$ Hence, the tank will be filled in 8 minutes.

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