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Railways Sample Paper RRB (Assistant Loco Pilot) Sample Test Paper-15

  • question_answer
    If \[(x-3)\,9(2x+1)=0,\] then the possible values of \[2x+1\] are:

    A)  0 only             

    B)  0 and 3          

    C)         \[-\frac{1}{2}\] and 3           

    D)         0 and 7          

    Correct Answer: D

    Solution :

    \[(x-3)(2x+1)=0\] \[\Rightarrow \] \[(x-3)=0\] or \[(2x+1)=0\] when \[x-3=0\]then \[x=3\] when \[2x+1=0\]then \[x=-\frac{1}{2}\] If \[x=3,\] then \[(2x+1)=7\] and \[2x+1=0\] when \[x=-\frac{1}{2}\] Possible value of \[(2x+1)\] are 0 and 7.


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