A) 40
B) 30
C) 20
D) 10
Correct Answer: B
Solution :
As, in first figure, |
\[\begin{matrix} 64 & {} & 36 & {} & 49\\ \downarrow& {} & \downarrow& {} & \downarrow \\ {{(8)}^{2}} & + & {{(6)}^{2}} & + & {{(7)}^{2}}\\ \end{matrix}\] |
\[8+6+7=21\] |
Similarly, in second figure, |
\[\begin{matrix} 121 & {} & 81 & {} & 100\\ \downarrow& {} & \downarrow& {} & \downarrow \\ {{(11)}^{2}} & + & {{(9)}^{2}} & + & {{(10)}^{2}}\\ \end{matrix}\] |
\[11+9+10=30\] |
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