question_answer

Kavi walks Northward upto 10 m. He turns left and walks 30 m. Finally, he turns left and walks 50 m. At what distance Kavi is now from his starting position?

A)  50 m               

B)  10 m

C)  20 m                           

D)  90 m

Correct Answer: A

Solution :

[a] According to the question, the direction diagram is drawn as shown in given figure

\[IO=10m\], \[\,OP=30m\], \[PF=50m\]

\[QI=OP=30m\], \[\,PQ=IO=10m\]

\[QF=PF-PQ=50-10=40m\]

F represents the final position,

\[\therefore \]Required distance,

In \[\Delta FQI\]   \[IF=\sqrt{{{(QI)}^{2}}+{{(QF)}^{2}}}=\sqrt{{{(30)}^{2}}+{{(40)}^{2}}}\]

\[=\sqrt{900+1600}\,\,\,\,\,=\sqrt{2500}=50m\]