| Directions: In each of the following questions two equations are given. You have to solve both the equations and find out values of x, y and give answer. [NICL (AO) 2014] |
| I. \[{{x}^{2}}-10x+21=0\] |
| II. \[{{y}^{2}}-16y+63=0\] |
A) If \[x>y\]
B) If \[x\le y\]
C) If \[x<y\]
D) If \[x\ge y\]
E) If relationship between x and y cannot be determined
Correct Answer: B
Solution :
| I. \[{{x}^{2}}-10x+21=0\] |
| \[x=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}=\frac{10\pm \sqrt{100-84}}{2}=7,\]3 |
| II. \[{{y}^{2}}-16y+63=0\] |
| \[y=\frac{16\pm \sqrt{256-252}}{2}=\frac{16\pm 2}{2}=9,\]7 |
| \[\therefore \] \[x\le y\] |
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