| Two numbers are in the ratio 3: 4. The product of their HCF and LCM is 2028. The sum of the numbers is |
A) 68
B) 72
C) 86
D) 91
Correct Answer: D
Solution :
| Let the numbers be 3x and 4x. |
| Then, HCF \[\times \] LCM = First number \[\times \] Second number |
| \[\therefore \] \[2028=3x\times 4x\] |
| \[\Rightarrow \] \[{{x}^{2}}=\frac{2028}{12}=169\]\[\Rightarrow \]\[x=13\] |
| \[\therefore \] Sum of numbers \[=(3\times 13)+(4\times 13)\] |
| \[=39+52=91\] |
You need to login to perform this action.
You will be redirected in
3 sec
