The sum of both digits of a two-digit number is 7. If the digits of the numbers are interchanged, the number so formed is greater than the original number by 27. Find the original number. [NICL (AO) 2015] |
A) 25
B) 26
C) 27
D) 28
E) 29
Correct Answer: A
Solution :
By going through option, we can eliminate the other 4. |
\[\therefore \] 25 is the correct option, as sum of both digit is 7. and by interchanging the position of the digit i.e. 25 turns into 52. |
Difference \[=52-25=27\] |
Alternate Method |
Let the digit at tens place be y and at one's place by x. |
Then, according to; the question, |
\[x+y=7\] ... (i) |
and \[-\,(10y-x)+(10x+y)=27\] |
\[\Rightarrow \] \[-\,9y+9x=27\] |
\[-\,y+x=3\] ... (ii) |
On solving Eqs. (i) and (ii), we get |
\[2x=10\]\[\Rightarrow \]\[x=5\] |
\[\therefore \] y = 2 |
So, number is 25. |
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