| A horse takes \[2\frac{1}{2}\,s\] to complete a round around a circular field. If the speed of the horse was 66 m/s, then the radius of the field is, \[\left[ take\,\pi =\frac{22}{7} \right]\] [SSC (10+2) 2014] |
A) 25.62 m
B) 26.52 m
C) 25.26 m
D) 26.25 m
Correct Answer: D
Solution :
| Circumference of circular field |
| \[=\,\,66\times \frac{5}{2}=33\times 5=165\,m\] |
| We know that, circumference \[=2\pi r\] |
| \[\Rightarrow \] \[165=2\times \frac{22}{7}\times r\] [where, r is the radius of field] |
| \[\Rightarrow \] \[r=\frac{165\times 7}{2\times 22}=\frac{105}{4}\] |
| \[\Rightarrow \] \[r=26.25\,\,m\] |
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