A girl of height 90 cm is walking away from the base of a lamp-post at a speed of 1.2 m/s. If the lamp is 3.6 m above the ground, then find the length of her shadow after 4 s. |
A) 8 m
B) 1.6 m
C) 2.8 m
D) 2 m
Correct Answer: B
Solution :
Let length of shadow = DE = x m |
BD = Distance covered by the girl in 4 s |
\[=1.2\times 4=4.8\text{ }m\] |
Also, in \[\Delta ABE\] and \[\Delta CDE\] |
and \[\angle B=\angle D\] |
\[\Rightarrow \] \[\angle A=\angle C\]and \[\angle E=\angle E\] |
\[\therefore \] \[\Delta ABE=\Delta CDE\] |
\[\therefore \]\[\frac{BE}{DE}=\frac{AB}{CD}\]\[\Rightarrow \]\[\frac{4.8+x}{x}=\frac{3.6}{0.9}\] |
\[\Rightarrow \] \[4.8+x=4x\]\[\Rightarrow \]\[x=1.6\,m\] |
You need to login to perform this action.
You will be redirected in
3 sec