If N is the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder, in each case. Then, sum of the digits in N is |
A) 4
B) 5
C) 6
D) 8
Correct Answer: A
Solution :
The greatest number N = HCF of \[(1305-x),\]\[(4665-x)\]and \[(6905-x),\] where x is the remainder, |
= HCF of \[(4665-1305),\]\[(6905-4665)\] and\[(6905-1305)\] |
HCF of 3360, 2240 and 5600 |
Again, |
\[\therefore \] \[N=1120\] |
Sum of digits \[=1+1+2+0=4\] |
You need to login to perform this action.
You will be redirected in
3 sec