| If \[a:b=c:d=e:f=1:2,\] then \[(pa+qc+re):(pb\,+qd+rf)\] is equal to |
A) \[p:(q+r)\]
B) \[(p+q):r\]
C) 2 : 3
D) 1 : 2
Correct Answer: D
Solution :
| \[\frac{a}{b}=\frac{c}{d}=\frac{e}{\text{f}}=\frac{1}{2}\]\[\Rightarrow \]\[\frac{pa}{pb}=\frac{qc}{qd}=\frac{re}{r\text{f}}=\frac{1}{2}\] |
| \[\Rightarrow \] \[\frac{pa+qc+re}{pb+qd+r\text{f}}=\frac{1}{2}\] |
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