If a 4 digit number is formed at random using the digits 1, 3, 5, 7 and 9 without repetition, thus the probability that it is divisible by 5 is |
A) \[\frac{4}{5}\]
B) \[\frac{3}{2}\]
C) \[\frac{1}{5}\]
D) \[\frac{2}{3}\]
Correct Answer: C
Solution :
Number of four-digit numbers which are formed with |
\[1,\]\[3,\]\[5,\]\[7,\]\[9={}^{5}{{P}_{4}}\] |
\[=5\times 4\times 3\times 2=120=n\,\,(s)\] |
The number which are divisible by \[5={}^{4}{{P}_{3}}\] |
\[=4\times 3\times 2=24=n\,\,(E)\] |
\[\therefore \] \[P\,\,(E)=\frac{n\,\,(E)}{n\,\,(S)}=\frac{24}{120}=\frac{1}{5}\] |
You need to login to perform this action.
You will be redirected in
3 sec