| If \[A:B=\frac{1}{2}:\frac{1}{3},\]\[B:C=\frac{1}{5}:\frac{1}{3},\] |
| then \[(A+B):(B+C)\] is equal to (SSC (CGL) Mains 2014] |
A) 9 : 10
B) 6 : 15
C) 5 : 8
D) 15 : 16
Correct Answer: D
Solution :
| \[A:B=\frac{1}{2}:\frac{1}{3}=3:2=9:6\] |
| \[B:C=\frac{1}{5}:\frac{1}{3}=3:5=6:10\] |
| \[\Rightarrow \] \[A:B:C=9:6:10\] |
| Let \[A=9k,\]\[B=6k\] and \[C=10k\] |
| Then, \[\frac{(A+B)}{(B+C)}=\frac{(9k+6k)}{(6k+10k)}=\frac{15k}{16k}=15:16\] |
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